TP1 - ESTATICA TERCERA PARTE

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MÉTODO DE CULLMAN

MÉTODO DE RITTER

OPCIÓN 1 ESC: 1CM=1KN

F

F

Fb

II

a

I

5m

5m a

A

A

m 5m

Fc

aux

aux

B

III B

aux b

c

5m

b

c

Fa

centro de momento I

centro de momento II

centro de momento III

CM a = 0

CM a = 0

CM c = 0

CM c = 0

CM b = 0

CM b = 0

P . Dp = Db . Fb

P . Dp = Dc . Fc

P . Dp = Da . Fa

8kn . 5m = 3,5m . Fb

8kn . 10m = 5m . Fc

8kn . 5m = 5m . Fa

40knm = 3,5m . Fb

80knm = 5m . Fc

40knm = 5m . Fa

Fb = 40knm 3,5m

Fc = 80knm 5m

Fa = 40knm 5m

Fb = 11,43kn

Fc = 16kn

Fa = 8kn

Intensidades F=8Kn Fa=7,9Kn Fb=11,12Kn Fc=15,88Kn MÉTODO DE CULLMAN OPCIÓN 2 ESC: 1CM=1KN

Fa

aux

B a

Fc

aux

b

c

Fb A

Intensidades F=8Kn Fa=7,9Kn Fb=11,12Kn Fc=15,88Kn

MÉTODO DE CULLMAN

MÉTODO DE RITTER

F c

F c

A

III

a

II

5m

5m

centro de momento I

centro de momento II

centro de momento III

CM c = 0

CM a = 0

CM a = 0

CM b = 0

CM c = 0

CM b = 0

P . Dp = Da . Fa

P . Dp = Db . Fb

P . Dp = Dc . Fc

8kn . 7,5m = 2,5m . Fa

8kn . 5m = 3,5m . Fb

8kn . 10m = 3,5m . Fc

60knm = 2,5m . Fa

40knm = 3,5m . Fb

80knm = 3,5m . Fc

Fa = 60knm 2,5m

Fb = 40knm 3,5m

Fc = 80knm 3,5m

Fa = 24kn

Fb = 11,43kn

Fc = 22,85kn

m

I

aux

2,5 m

5

aux

5

3,

B

m

a

3,

PARTE 2

Agustina Pilar Forno Ortiz Verónica Florencia Pepe Alexis Exequiel Petelin Ana Camila Boy Mariano Albornoz

3, 5

GRUPO 6

7,5 m

Fb b b

Fc

aux

Fa

ESC: 1CM=1KN

Intensidades F=8Kn Fa=23,56Kn

Fb=10,9Kn

Fc=22,33Kn