Microsoft Word - Wzory

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Transformator: ∆ ∆ % = = 100 ∆ % = 100 > 2,5 ⇒ = ∆ ∆ % = = 100 =−

Δ Δ

=

%

∆

=

(

(

)

(

=Δ

+

(

2

%

=

100

=

√3| | = √2 =√ + = √3 Sieć zasilająca: =

−

)

)

=

Straty energii: Δ =Δ Δ =Δ 2 = 3 Zwarcia:

100 Dławik: ∆ % ∆ % = = 100 100√3 Spadki: ∆ = ∗ ∆ = ( + )( + ) ∆ = (∆ ) = − Metoda odcinkowa: ∆

=

(

−

)

)

(

= 0,995 ; = 0,1 > 35 ⇒ = Obciążalność: ≤ ( )

)

(

)

(

)

(

)

=

(

− −

)

Metoda momentów: ∆

=

∆

≥

−

=

Dwustronnie zasilane: ∑ Δ = ± =

∑

±

Δ

Stała gęstość: =

Δ

∑ =

( (

=Δ

Δ

Δ Δ

=3 =

Δ

=Δ

(

Δ

%

=

> 2,5

)

)

cos

=Δ

=Δ

Kompensacja: ∆ −∆ = =3

+ = Δ

%

⇒Δ

−Δ %

Δ

%

100 %

=Δ

%

(

=

)

(

+ =Δ

Straty mocy biernej: + Δ =

=Δ

)

(

Δ

)

)

Δ

Δ

)

Δ

Linia II rodzaju:

=

(

)

Straty mocy czynnej: Δ =3

Δ

)

Przekrój: Stały przekrój:

−

=

(

(

(

+

)

(

)